is a regular parametrisation of some part \(C\subset\partial D\) consistent with the orientation of \(\partial D\text{.}\) By definition of the line integral we have
We can view the integrand on the right hand side as a dot product of \(\vect f\) with the vector \((\gamma_2'(t),-\gamma_1'(t))\text{.}\) We rescale the latter to unit length and define
Observe that \(\vect n(t)\) is perpendicular to the positive unit tangent vector \(\vect\tau(t)=\vect\gamma'(t)/\|\gamma'(t)\|\text{.}\) As it is outward pointing, it is called the outward pointing unit normal to \(D\text{.}\) Both vectors are shown in Figure 11.1.
Figure11.1.Positive tangent and outward pointing unit normal vectors.
Let \(\Delta s\) denote a very small line element. If \(\vect f\) models the motion of a fluid (direction and velocity of fluid at a given point) then \(\vect f\cdot\vect n\Delta s\) is the flux across \(\partial D\) through the line element \(\Delta s\text{,}\) and \(\vect f\cdot\vect n\Delta s\) is the approximate amount of fluid flowing across the boundary \(\partial D\) through \(ds\text{.}\) The situation is depicted in Figure 11.2. Note that the area of the parallelogram and the rectangle are the same.
Figure11.2.Flux across a boundary element of \(\partial D\text{.}\) The parallelogram and the rectangle have the same area.
Hence the integral on the right hand side of (11.1) represents the total flux of \(\vect f\) across \(C\subset \partial D\text{.}\) Note that the above arguments are completely analogous to those used in Section 9.6 to find the flux of a vector field in space across a surface. Going back to the original formula we see that
Often the divergence of a vector field is written using the nabla operator in Definition 8.15. Formally, \(\divergence\vect f\) is the scalar product of \(\nabla\) with \(\vect f\text{,}\) and so we write